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Post by jlowder23 on May 26, 2015 6:27:12 GMT -7
I've got a 2x12 cab loaded with blues. I believe they are 16 ohm each wired paralell which would give me an 8 ohm load??? If I wanted to swap one out and replace it with a gold, what ohm rating would the gold need to be? I know I would have to change the wiring to series and put the gold first, but would I need a 16 ohm gold to use with the 16 ohm blue??
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Post by doctorice on May 26, 2015 7:07:12 GMT -7
Yup, two 16s in parallel creates an 8 ohm load. It would be a good idea to verify the speakers' stated impedances. It's usually marked somewhere, often near/at the terminals.
If you get a 16-ohm Gold, then a direct swap without re-wiring would keep you at 8 ohms.
You can run an 8 and 16 in parallel, giving a load a bit over 5 ohms. Plug into a 4-ohm output jack on the amp in that case.
If you want to do the series wiring, like a Z Wreck cab -- I think Doc uses a pair of 8 ohms -- then the impedances simply add up: 16 + 16 = 32, 8 + 8 = 16, 8 + 16 = 24. You'd use the 16-ohm jack, probably, although either of the lower impedance outputs (8 and 4) would be OK, i.e., safe for your amp's health.
Added: There's no "requirement" to change to series configuration. It's up to you. What you don't want to do is create a bad mismatch by putting a lower impedance load (speakers) into a higher impedance output jack. That's bad for the amp.
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Post by Mark (Basement Enthusiast) on May 26, 2015 7:40:48 GMT -7
Important note, too--two Blue's in parallel will be rated for a max of 30 Watts (one Blue can handle 15 W). But a Blue & Gold in parallel will also be rated for a max of 30 Watts; the higher 50 W handling of the Gold will not be realized in that wiring setup.
You can google speaker wirings and how to calculate ratings all day, so I won't bother going through all that here. But bottom line, adding one Gold with a Blue in parallel will not increase your safe power-handling capacity overall. [It may, however, alter the tone--which is a great idea to try mixing them.]
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Post by jlowder23 on May 26, 2015 10:23:03 GMT -7
I guess I should've clarified. Is is possible to hook up an 8 ohm gold with a 16 ohm blue?
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Post by headshrinker (Marc) on May 26, 2015 10:34:29 GMT -7
As Mike said above, put them in parallel and you will get roughly a 5 Ohm load and go into the 4 ohm tap and you will be good. As Mark said above, remember you have a 30 watt cab at that point, even though the gold is a 50 watt speaker.
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Post by doctorice on May 26, 2015 10:37:22 GMT -7
As Mike said above, put them in parallel and you will get roughly a 5 Ohm load and go into the 4 ohm tap and you will be good. As Mark said above, remember you have a 30 watt cab at that point, even though the gold is a 50 watt speaker.
Or you can put them in series, getting a 24 ohm load, and plug into the 16 ohm out. I think Z puts the Gold first in the series setup on the Wreck. That will soak up some power, meaning there'll be less going to the blue.
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Post by Mark (Basement Enthusiast) on May 26, 2015 11:02:50 GMT -7
I guess I should've clarified. Is is possible to hook up an 8 ohm gold with a 16 ohm blue? Yes, and you can do so, as follows... As Mike said above, put them in parallel and you will get roughly a 5 Ohm load and go into the 4 ohm tap and you will be good. BUT, here's a twist with doing that (different as I'd stated above)--with 2 different impedance speakers in parallel, the lower-impedance one will take more current, thus soaking up more power, etc. In this particular case (running the 8-ohm Gold and 16-ohm Blue in parallel out of the 4-ohm amplifier output) your overall cab power-handling limit will be approx. 45 Watts. This is why nobody ever recommends mixing speaker impedances... because, if for no other reason, it gets super confusing super quickly.
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Post by benttop (Steve) on May 27, 2015 15:56:00 GMT -7
...and the speaker soaking up more power will be louder. Quite a lot louder than the other.
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